[TriLUG] possible awk/grep question
Joseph Mack NA3T
jmack at wm7d.net
Sun Dec 30 18:38:39 EST 2007
On Sun, 30 Dec 2007, Craig Taylor wrote:
> As with anything else in Linux, there's a million ways...
>
> for USR in `cat /etc/group | grep ^user | sed "s/^.*:100://" | sed "s/,/
> /g"`; do
> echo $USR
> done
Hi Craig,
thanks for the suggestion
Having thought about this for a week or so now, and
not having an answer, after posting here, I googled and came
up with
cat /etc/passwd | awk 'BEGIN { FS = ":" } $4 == "100" {print}'
I didn't know about the
$4 == "100"
construct
Joe
--
Joseph Mack NA3T EME(B,D), FM05lw North Carolina
jmack (at) wm7d (dot) net - azimuthal equidistant map
generator at http://www.wm7d.net/azproj.shtml
Homepage http://www.austintek.com/ It's GNU/Linux!
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