[TriLUG] Linksys long in the tooth?

[Jim Ray]

I had one heck of a time chunking boron, phosphorous and silicon in my Cuisinart and coming out with a semiconductor yet seem to remember a threshold of 0.7 V due to semiconductor physics (nevermind is it a wave or particle). The trend I have seen is a lowering of the voltage such that the transistors do not go as far into saturation as they used to go years gone by when 5V was popular.

I suspect we will continue to see a lowering of the voltage, increasing of the speed and lowering of the power on a transistor-by-transistor basis.

Reliability, however, is determined more by statistics following semiconductor fabrication more so than voltage of a power supply.

Regards,
 
Jim
 
Jim Ray, President
Neuse River Networks
tel: 919-838-1672 cell: 919-606-1772
http://www.NeuseRiverNetworks.com
 
Connecting You to the World since 1997 with Managed Services, IT Outsourcing and Network Communications Systems for Voice, Video and Data 



-----Original Message-----
From: trilug-bounces at trilug.org [mailto:trilug-bounces at trilug.org] On Behalf Of James Brigman
Sent: Tuesday, January 15, 2008 10:59 PM
To: Triangle Linux Users Group General Discussion
Subject: Re: [TriLUG] Linksys long in the tooth?

No...I'm not assuming anything, thank you. Neither did I say the world
is flat or windows is cool. 

P=I*I*R --> power varies as to the square of the current, through any
given heat-generating, power-consuming device.

Aha! So why are new low-power CPU's lower voltage! Dag nabbit, I didn't
say anything about voltage. But for what it's worth, the lower voltage
pushes far lower currents across the fixed semiconductor voltage
threshholds. Whoops. P=I*I*R again.

Lower voltage, higher current products simply seem to be less reliable
than higher voltage, lower current products. Tha End.

JKB

On Tue, 2008-01-15 at 12:32 -0500, Randy Barlow wrote:
> jbrigman at nc.rr.com wrote:
> > Lesson to the rest of us - try to avoid equipment that uses 5v rather than 12v, it appears the lower voltage, higher current contributes to early failure - I've got at least four instances of this just in my own experience. 
> 
> I don't think this is really true.  You assume here that two devices use
> equal amount of power.  A 12 V device could very well use the same
> current as a 5 V device and more than double the power consumption.
> Power consumption is what causes heat, which is one thing that can lead
> to failure.
> 
> -- 
> Randy Barlow
> http://electronsweatshop.com

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